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3 years ago

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A model rocket is 3 inches long. The real rocket is 120 feet long.

1 answer:

Nana76 [90]3 years ago

5 0

The units are the complete story on this question. All of the choices are over 1 so the units make the answer over one. It takes more feet than it does inches to make the scale. The correct units are 120 feet / 3 inches. That makes A and B both incorrect.

You can't get 360 by any method but multiplication. The units for multiplication would be ft*in. So D is wrong. That only leaves you with C which is the answer.

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The scale on a map is 2 centimeters= 50 kilometres.Two rivers on a map are located 9.3 centimeters apart.What is The actual dist

Yuki888 [10]

Answer:

The actual distance between the two rivers is <u>232.5 kilometers</u>.

Step-by-step explanation:

GIven:

The scale on a map is 2 centimeters= 50 kilometres.Two rivers on a map are located 9.3 centimeters apart.

Now, to find the actual distance between the two rivers.

Let the actual distance between the two rivers is $x.$

The two rivers on the map is located apart of 9.3 centimeters.

According to the scale on the map is 2 centimeters = 50 kilometers.

<em>So, 2 centimeters is equivalent to 50 kilometers.</em>

<em>Thus, 9.3 centimeters is equivalent to </em> $x.$ <em />

Now, to solve by using cross multiplication method:

$\frac{2}{50} =\frac{9.3}{x}$

<em>By cross multiplying we get:</em>

<em /> $2x=465$ <em />

<em>Dividing both sides by 2 we get:</em>

$x=232.5\ kilometers.$

Therefore, the actual distance between the two rivers is 232.5 kilometers.

6 0

3 years ago

Help please with this question

torisob [31]

Answer: 70ft

Step-by-step explanation:

ht= (-3)^2 + 15(3) + 16

ht= 9 + 45 + 16

ht= 70

3 0

3 years ago

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What is <br>if 5y +2x <br>simplify 2y×4x

ratelena [41]

Answer:

2*x

Step-by-step explanation:

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6 0

2 years ago

Does anybody know this!???

hodyreva [135]

Answer:

The third one

Step-by-step explanation:

7 0

3 years ago

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The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the

Taya2010 [7]

Answer:

$L_1 = 4$

And $L_2 = 3 +4 = 7$

Step-by-step explanation:

For this case we assume that for the first square we have the following dimensions:

$A_1 = L^2_1$

And we know that:

$L_2 = 3 + L_1$

And the area for the second square would be:

$A_2 = L^2_2 = (3+L_1)^2 = 9 + 6L_1 + L^2_1$

And we know that the sum of areas is 65 so then we have this:

$A_1 + A_2 = 65$

And replacing we got:

$L^2_1 + 9 + 6L_1 + L^2_1 = 65$

$2L^2_1 +6L_1 - 56=0$

We can divide the last expression by 2 and we got:

$L^2_1 + 3L_1 -28=0$

And we can factorize the last expression like this:

$(L_1 + 7) (L_1 -4) =0$

And we have two solutions for $L_1$ and we got:

$L_1 = 4, L_1 = -7$

Since the length can't be negative we have this:

$L_1 = 4$

And $L_2 = 3 +4 = 7$

4 0

4 years ago

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