Calculate $x^{6} + (y^{2} \div z^3)\cdot w^3$ assuming that $x=2$, $y=3^2$, $z=3$, and $w=4$.
1 answer:
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Answer:
A
Step-by-step explanation:
So we have the equation:
To solve for x, subtract 4 from both sides:
The left side cancels. Subtract on the right:
So, the value of x is 3.
And our answer is A.
And we're done!
