Answer:
(a) k = C + 273.15, F = 1.8(k - 273.15) + 32
(b) k = 296.15
(c) 25 celcius is greater than 300 kelvis.
Step-by-step explanation:
(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.
C = k - 273.15
C + 273.15 = k
k = C + 273.15
F = 1.8(k - 273.15) + 32
(b) for this one you have to substitute in the previous equation and solve for k.
23 = k - 273.15
k = 23 + 273.15
k = 296.15
(c) you have to convert either kelvins to celcius or celcius to kelvins.
C = k - 273.15
C = 300 - 273.15
C = 26.85
So 25 celcius is greater than 300 kelvis.
Answer:
Step-by-step explanation:
is essentially (you are squaring , so multiplying it by itself), so to simplify, you would need to distribute.
A good way to go about this is using the F.O.I.L. method, multiplying the First numbers in the parentheses, then the Outers, then Inners, and finally, Lasts.
>> >> >>
()
After doing so, you would end up with , and after combining like terms, .
To write the expression in standard form, though, just order the terms from highest to lowest power!
Answer:
Option b
Step-by-step explanation:
A function is even if and only if f(-x) = f(x).
This means that there is the same value of y for and for
Where is any point belonging to the function .
Therefore you must select a graph whose ordered pairs are of the form and
Therefore the correct answer is option b. Assume that each box in the graph equals 1 unit. Then, for x = 2 y = -3 and for x = -2 y = -3. Then it is shown that the function is even.