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3 years ago

Which of these is an example of driving at an average rate of 20 miles per hour?

Mathematics

1 answer:

dlinn [17]3 years ago

4 0

Driving 40 miles in 2 hours is the answer

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The bag has 2 yellow cubes, 5 green cubes, and 3 red cubes. Without replacing the yellow cube, what is the probability of select

laila [671]

32% chance of selecting red at random.

3 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

3 years ago

''Write an equation for line ` l `.''

lawyer [7]

Y=4 I’m pretty sure

3 0

3 years ago

Andres boards a Ferris wheel at the 3-o'clock position and rides the Ferris wheel for multiple revolutions. The Ferris wheel rot

Gelneren [198K]

Answer:

a) r(t) = 0.783t radians

b) h(t) = 30cos(0.783*t) feet

Step-by-step explanation:

The situation is depicted in the picture attached

<h3>(see picture) </h3>

Since the angular speed is constant, to find an expression for the angle r(t) in radians we just cross-multiply using the fact that 1 min = 60 seconds

4.7 radians __________ 60 seconds

r(t) radians ____________ t seconds

$\large \displaystyle\frac{4.7}{r(t)}=\displaystyle\frac{60}{t}\Rightarrow r(t)=(4.7/60)t \Rightarrow\\\\\boxed{r(t)=0.783t\;rad}$

The height h(t) after t seconds is given by

h(t) = 30cos(r(t)) ===>

h(t) = 30cos(0.783*t) feet

7 0

3 years ago

Last questions on this quiz (I always get confused on finding the x value)

zimovet [89]

For the first one, we know that is a right angle. right angles are 90 degrees. if we subtract 90 - 49 that equals 41. so the second value needs to equal 41. since we have a 3 there already, we are going to subtract 41-3, which is 38. x = 38

3 0

3 years ago