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3 years ago

Divide Rs 480 in the ratio of 5:7

Mathematics

2 answers:

patriot [66]3 years ago

6 0

Hey!!

Solution,

Let the ratios be 5x and 7 X

5x+7x=480

or,12x=480

or,X=480/22

X=40

Replacing value,

5x =5*40=200

7x=7*40=280

The answers are 200 and 280

Hope it helps

Good luck on your assignment

lutik1710 [3]3 years ago

5 0

Let the ratios be 5x and 7x

★ According to the question,

5x+7x=480

=> 12x=480

=> x = 480/12

=> x = 40

Now,

5x = 5 × 40=200

7x = 7 × 40=280

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4 years ago

Read 2 more answers

Please help me to solve this

zzz [600]

Answer:

Below in bold.

Step-by-step explanation:

First find the height by use Pythagoras theorem on the right triangle:

h = sqrt (5^2 - 4^2)

= sqrt 9

= 3.

Volume of the prism = area of the triangle * length

= 1/2 * 3 * 4 * 10

= 1/2 * 12 * 10

= 60 cm^3.

Total area = area of 2 triangles + area 0f 3 rectangles

= 2 * 1/2 * 3 * 4 + 3 * 10 + 4 * 10 + 5 * 10

= 12 + 30 + 40 + 50

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3 0

3 years ago

<img src="https://tex.z-dn.net/?f=solve%20for%20%22m%22%20t%3D%5Cfrac%7Bms%7D%7Bm%2Bn%7D" id="TexFormula1" title="solve for &quo

dalvyx [7]

Answer:

$\boxed{\sf \ \ \ m = -\dfrac{tn}{t-s} \ \ \ }$

Step-by-step explanation:

Hello,

let s assume that m+n is different from 0

we have this equation and we need to find m as a function of t, s, and n

$t=\dfrac{ms}{m+n}$

<=>

$(m+n)*t=ms\\\\ tm+tn=sm\\ (t-s)m = -tn\\ m = -\dfrac{tn}{t-s}$

for t-s different from 0, so t different from s

hope this helps

4 0

3 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

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3 years ago

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elena-s [515]

Answer:

answer is c makes sense because you just add 1.25 x 20

3 0

3 years ago

Divide Rs 480 in the ratio of 5:7​

Divide Rs 480 in the ratio of 5:7