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velikii [3]
3 years ago
8

(sin 9x)'what is the derivative of sin 9x​

Mathematics
2 answers:
Ne4ueva [31]3 years ago
6 0

Answer:

57

Step-by-step explanation:

Murljashka [212]3 years ago
5 0

Answer:

hi

Step-by-step explanation:

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A THREE DIMENSIONAL FIGURE IS SHOWN. WHICH NET REPRESENTS THE FIGURE??
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Answer:

Top left.

Step-by-step explanation:

Fold the three squares together, then each triangle up.

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Question 2 of 10
rusak2 [61]

Answer:

4

Step-by-step explanation:

Since the base angles are the same, the side have to be the same

ML = MN

4x = x+3

Subtract x from each side

4x-x = x+3-x

3x= 3

Divide by 3

3x/3 = 3/3

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Answer:

(8+24)÷(12x4) the correct answer is B

7 0
3 years ago
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Use the Laplace transform to solve differential equation
Inessa [10]
Using Laplace transform we have:L(x')+7L(x) = 5L(cos(2t))sL(x)-x(0) + 7L(x) = 5s/(s^2+4)(s+7)L(x)- 4 = 5s/(s^2+4)(s+7)L(x) = (5s - 4s^2 -16)/(s^2+4)
=> L(x) = -(4s^2 - 5s +16)/(s^2+4)(s+7) 
now the boring part, using partial fractions we separate 1/(s^2+4)(s+7) that is:(7-s)/[53(s^2+4)] + 1/53(s+7). So:
L(x)= (1/53)[(-28s^2+4s^3-4s^2+35s-5s^2+5s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]L(x)= (1/53)[(4s^3 -37s^2 +40s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]
denoting T:= L^(-1)and x= (4/53) T(s^3/(s^2+4)) - (37/53)T(s^2/(s^2+4)) +(40/53) T(s^2+4)-(4/53) T(s^2/s+7) +(5/53)T(s/s+7) - (16/53) T(1/s+7)
4 0
3 years ago
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