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solong [7]
3 years ago
9

There is 20 students in mr.millers algebra class. 14 of the students are females. if mr.miller selects a student at random, what

is the probability that he will select a male
Mathematics
1 answer:
Romashka [77]3 years ago
5 0
7/10 or 70%!!

Hope this helps (:
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(a-b) ( a+b) simplify​
BlackZzzverrR [31]

Answer:

a^2 - b^2

Step-by-step explanation:

1. (a)(a)+(a)(b)+(-b)(a)+(-b)(b)

2. a^2 + ab - ab - b^2

3. a^2 - b^2

4 0
3 years ago
Boy boy boy boy boy boy boy boy boy
ANEK [815]

Answer:

Hi welcome to brainly the happiest website on earth.

Step-by-step explanation:

5 0
3 years ago
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PLEASE ANSWER ASAP IF ANSWERED WITHIN 30 MINUTES YOU WILL RECEIVE BRAINLIEST
Hunter-Best [27]
A. 9.3 x 10^7 miles
B. 4 x 10^-2 inches
C. 5.89248 x 10^12 inches
D. 1.47312 x 10^14 fireflies
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3 years ago
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Let g(x) = 2x and h(x)= x^2 -4. find (g o h)(0)
finlep [7]
The answer is -8

====================================================

Explanation:

There are two ways to get this answer

Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8

-----------------------

The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4

g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8

Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8

Regardless of which method you use, the answer is -8

5 0
3 years ago
Based on the table, what is Nick's rate?
Murrr4er [49]
21 /3 = 7
35 / 5 = 7
63 / 9 = 7

 his rate is B. 7 yds/sec

5 0
3 years ago
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