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3 years ago

9

There is 20 students in mr.millers algebra class. 14 of the students are females. if mr.miller selects a student at random, what

is the probability that he will select a male

1 answer:

Romashka [77]3 years ago

5 0

7/10 or 70%!!

Hope this helps (:

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If Kim has 45 stickers and her sister steals 20 of them how many stickers does Kim have left?

nirvana33 [79]

Answer:

No, Dolly won't have enough money to buy the bracelet.

Step-by-step explanation:

$30.00 - $25.00 = $5.00

$10.00 is more than $5.00

<em>hope this helps :)</em>

8 0

3 years ago

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

Joel is looking at a costs for using a gym. He could pay $50 per month for unlimited use or he could pay $12 per month plus $4 p

just olya [345]

Answer:

10

Step-by-step explanation:

4 x 10 = 40

40 + 12 = 52

6 0

3 years ago

Simplify: 3r+n²-r+5-2n+2

lutik1710 [3]

3r+n2−r+5−2n+2<span />=3r+n2+−r+5+−2n+2=3r+n2+−r+5+−2n+2<span />=(n2)+(−2n)+(3r+−r)+(5+2)<span />=n2+−2n+2r+7<span /><span />
=n2−2n+2r+7

7 0

3 years ago

Read 2 more answers

Jennie has 177 more songs downloaded on her mp3 player than Diamond. Together, they have 895 songs downloaded. What system of eq

mr_godi [17]

With the information given, we can set up the following system of equations:

$x + y = 895$
$x - y = 177$

x represents how many songs Jennie has, and y represents how many songs Diamond has.

6 0

3 years ago

Read 2 more answers