Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
Answer:
1,12×10^6
Step-by-step explanation:
Answer: i think its the 3rd one
Step-by-step explanation:
Answer:
Exact Form:
100/3
Decimal Form:
33.3
Mixed Number Form:
33 1/3
<em><u>i hope this helped at all.</u></em>
Less than greater than equal Too
