If l || m, classify the marked angle pair and give their relationship, then solve for X.

Father to his first biological son true or false?

FromTheMoon [43]

Answer:

True

Step-by-step explanation:

have a great day!

5 0

3 years ago

Write parametric equations of the line through the points (7,1,-5) and (3,4,-2). please use the first point as your base-point w

Roman55 [17]

Given:

A line through the points (7,1,-5) and (3,4,-2).

To find:

The parametric equations of the line.

Solution:

Direction vector for the points (7,1,-5) and (3,4,-2) is

$\vec {v}=\left$

Now, the perimetric equations for initial point $(x_0,y_0,z_0)$ with direction vector $\vec{v}=\left$ , are

$x=x_0+at$

$y=y_0+bt$

$z=z_0+ct$

The initial point is (7,1,-5) and direction vector is $\vec {v}=\left$ . So the perimetric equations are

$x=(7)+(-4)t$

$x=7-4t$

Similarly,

$y=1+3t$

$z=-5+3t$

Therefore, the required perimetric equations are $x=7-4t, y=1+3t$ and $z=-5+3t$ .

5 0

3 years ago

|-3|=_________ how do you do this. so you know this is high school work.

ludmilkaskok [199]

These | | simple mean absolute value. Absolute value is simply the number positive, for example, the absolute value of -3 is simply 3

4 0

3 years ago

Read 2 more answers

An independent-measures research study was used to compare two treatment conditions with n= 12 participants in each treatment. T

Maurinko [17]

Answer:

(a) The data indicate a significant difference between the two treatments.

(b) The data do not indicate a significant difference between the two treatments.

(c) The data indicate a significant difference between the two treatments.

Step-by-step explanation:

Null hypothesis: There is no difference between the two treatments.

Alternate hypothesis: There is a significant difference between the two treatments.

Data given:

M1 = 55

M2 = 52

s1^2 = 8

s2^2 = 4

n1 = 12

n2 = 12

Pooled variance = [(n1-1)s1^2 + (n2-1)s2^2] ÷ (n1+n2-2) = [(12-1)8 + (12-1)4] ÷ (12+12-2) = 132 ÷ 22 = 6

Test statistic (t) = (M1 - M2) ÷ sqrt [pooled variance (1/n1 + 1/n2)] = (55 - 52) ÷ sqrt[6(1/6 + 1/6)] = 3 ÷ 1.414 = 2.122

Degree of freedom = n1+n2-2 = 12+12-2 = 22

(a) For a two-tailed test with a 0.05 (5%) significance level and 23 degrees of freedom, the critical values are -2.069 and 2.069.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 falls outside the region bounded by the critical values.

(b) For a two-tailed test with a 0.01 (1%) significance level and 23 degrees of freedom, the critical values are -2.807 and 2.807.

Conclusion:

Fail to reject the null hypothesis because the test statistic 2.122 falls within the region bounded by the critical values.

(c) For a one-tailed test with 0.05 (5%) significance level and 23 degrees of freedom, the critical value is 1.714.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 is greater than the critical value 1.714.

6 0

3 years ago

If cosa=1/2(a+1/a), verify that. cos2a=1/2(a²+1/a²)

Alborosie

Answer:

see explanation

Step-by-step explanation:

using the identity

cos2a = 2cos²a - 1 , then

cos2a

= 2[ $\frac{1}{2}$ (a + $\frac{1}{a}$ ) ]² - 1

= 2 [ $\frac{1}{4}$ (a² + $\frac{1}{a^2}$ + 2) ] - 1

= $\frac{1}{2}$ (a² + $\frac{1}{a^2}$ ) + 1 - 1

= $\frac{1}{2}$ (a² + $\frac{1}{a^2}$ ) ← thus verified

3 0

2 years ago