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Minchanka [31]
3 years ago
12

Can someone solve this ASAP.

Mathematics
2 answers:
vazorg [7]3 years ago
4 0
What’s the question??
Dimas [21]3 years ago
3 0

Answer:

where's the picture?

Step-by-step explanation:

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12y +6 is the answer to that question
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Sketch the region of integration for the following integral. ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ
solong [7]

Answer:

The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

Step-by-step explanation:

We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line  x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

3 0
3 years ago
F(x,y)=4x^2y^3-square root 2x+5y in the direction of =-1,4
dedylja [7]

Answer:

frygvhbe 0qcin3ywhjwjhw

Step-by-step explanation:

wbhbjhxw

wjskjwn

djwnkoqn[

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V = l.W.H

3(5)(4) = 60 units

3 0
3 years ago
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