For all exponents, (a^n a^m) = a^(n+m)
apply same rules (X^3X^2)/(4*3)
Combine powers. (X^3X^2)/4*3 = X^(3+2)/4*3
X^5/12
The sum of the given series can be found by simplification of the number
of terms in the series.
- A is approximately <u>2020.022</u>
Reasons:
The given sequence is presented as follows;
A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021
Therefore;
The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;
Therefore, for the last term we have;
2 × 2043231 = n² + 3·n + 2
Which gives;
n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0
Which gives, the number of terms, n = 2020


Which gives;


Learn more about the sum of a series here:
brainly.com/question/190295
Answer:
The second one
Step-by-step explanation:
A linear function will always increase or decrease by the same amount:
The first one adds eight for every increase of 1 in the x value
The third one subtracts three for every increase of 1 in the x value
However,
The second one starts by adding three, and then adds 1.5 for the rest
The second table is nonlinear
Answer:
5/8
Step-by-step explanation:
the range is the largest number minus the smallest number so
1 1/4 - 5/8
5/4 - 5/8
you would take 5/4 *2 to get like denominators so,
10/8-5/8= 5/8