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Artist 52 [7]
3 years ago
14

Evan, James, and Burt are fishing in a lake that has 200 fish. They are going to be fishing for three hours. What is the probabi

lity that they each will catch 3 fish?
Mathematics
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

The probability that they each will catch 3 fish is 0.000063956

Step-by-step explanation:

The hyper geometric distribution is used to solve this as it has a population, a sample , number of successes  for both the population and sample.

Here

Population size= N =200

Sample size= n =9= (3*3)

Number of successes in population = k = 3 hours

Number of successes in sample = x= 3

Applying the hyper geometric distribution

P (x=3) = kCx *(N-k) C (n-x)/ N Cn

   = 3 C 3 * 197 C 6/ 200 C 9

    =0.000063956

The probability that they each will catch 3 fish is 0.000063956

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Shkiper50 [21]
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8 0
4 years ago
Jerry is a judge. He hears 5 cases in 2 3/8 hours. How many cases does he hear per hour
Serggg [28]

Answer:

Jerry does 2.11 cases per hour (Rounded to 2 decimal places). As we cannot do 0.11 cases. We can say Jerry does 2 cases per hour.

Step-by-step explanation:

to find the number of cases per hour, we have to divide the number of cases by number of hours taken for those cases,

Number of cases per hour = \frac{5cases}{2\frac{3}{8} hours}

                                             =\frac{5}{\frac{19}{8} } \\ cases per hour

                                             =\frac{5*8}{19} cases per hour

                                             =\frac{40}{19} cases per hour

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4 years ago
What are the solutions to the equation
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Lets solve it
first multiply each term by x :-

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3 0
3 years ago
Read 2 more answers
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<h3></h3><h2>⭐ Development:</h2><h3></h3>

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\large {\text {$ \sf \cfrac{1}{2x^2} -2 = 0 $}}

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\large {\text {$ \sf \cfrac{1}{2x^2}\cdot \:2x^2-2\cdot \:2x^2=0\cdot \:2x^2 $}

                 \searrow

                     \large {\text {$ \sf 1-4x^2=0$}}

  • We have to write in standard form...

\large {\text {$ \sf -4x^2+1 = 0 $}}

<u>                                                                                                      </u>

<u />

\large {\text{$\sf x=\cfrac{-b\pm\sqrt{b^2-4ac}}{2a} \quad\rightarrow\quad x=\cfrac{-0\pm\sqrt{0^2-4\cdot (-4) \cdot1} }{2\cdot (-4) } \:\rightarrow\:\: x=\cfrac{-0^2 \pm4}{2 \cdot(-4)}    $}}  

                                                                                                                         

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