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3 years ago

Question 6: The rectangle shown on the grid is reflected across the Y-axis. 1 point

Mathematics

1 answer:

Oksanka [162]3 years ago

8 0

Answer:

-5,6

Step-by-step explanation:

cause you stared at 6 then you go down

You might be interested in

What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?

scoray [572]

Answer:

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to c} x = c$

Special Limit Rule [L’Hopital’s Rule]:
$\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}$

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]:
$\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify given limit.

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}$

Step 2: Find Limit

Let's start out by directly evaluating the limit:

[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}$

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

[Limit] Apply Limit Rule [L' Hopital's Rule]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}$
[Limit] Differentiate [Derivative Rules and Properties]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}$
[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}$

∴ we have evaluated the given limit.

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Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

3 0

1 year ago

What property is this out of distributive,associative,and communitive properties?

kherson [118]

Communitive Property is the correct one

3 0

3 years ago

Read 2 more answers

If a sled cost 99.50, and the markup is 95%, what's the selling price?

Mamont248 [21]

It is $94.52
99.5% of 100=

6 0

3 years ago

Find the x and y of x-3y=15 and -2x-4y=10

Minchanka [31]

Use elimination to create a one variable equation.

x-3y=15 -> 2x-6y=30

2x-6y=30

+(-2x-4y=10)

------------------

-10y=40

Then solve (for y in this case).

y=-4

Now we can use the value for y to solve for x.

x-3y=15 -> x-3(-4)=15 -> x=3

3 0

3 years ago

75 minutes to days using multi step unit conversions 75/1 is the first step I've taken and I need at least 3 steps I'm about to

Paha777 [63]

Stop ! Don't do something you might regret. It's not as bad as you think.

Minutes to days, eh ? What conversions could we find that might help ?
How about . . .

1 hour / 60 minutes

1 day / 24 hours

Both of those fractions are equal to ' 1 ', so we can freely multiply any quantity
by either one or both of them, without changing the value of the quantity.
The conversion you want might look something like this ...

(75 minutes / 1) x (1 hour / 60 minutes) x (1 day / 24 hours) .

After canceling units from top and bottom where possible,
you have ...

(75 x 1 x 1 day) / (1 x 60 x 24) = 0.05208333... day

and your head is still right where it belongs, ready to fight another day.

4 0

3 years ago