What is the equation of the linear function represented by the table?

Mathematics

2 answers:

3241004551 [841]3 years ago

8 0

Answer:

gggggggggg

Step-by-step explanation:

gggggggggggg

Bezzdna [24]3 years ago

5 0

Answer: ya daddy ate ma cat and i liked it

Step-by-step explanation:

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Identify the equation in slope-intercept for for the line containing the point (-3,5) and patella to y = -2/3x+5/3

Olegator [25]

Answer:

Y = - 2/3 x + 3

Step-by-step explanation:

y = -2/3x+5/3

Slope = -2/3. .. parallel line has same slope

For (- 3 , 5)

Y intercept = y - my = 5 - ( (-2/3) x (-3) ) = 3

Y = slope x X + y intercept

Y = - 2/3 x + 3

8 0

3 years ago

Infinite over E n=1 4(0.5)^n-1

yan [13]

Answer:

S = 8

Step-by-step explanation:

An infinite geometric series is defined as limit of partial sum of geometric sequences. Therefore, to find the infinite sum, we have to find the partial sum first then input limit approaches infinity.

However, fortunately, the infinite geometric series has already set up for you. It’s got the formula for itself which is:

$\displaystyle \large{\lim_{n\to \infty} S_n = \dfrac{a_1}{1-r}}$

We can also write in summation notation rather S-term as:

$\displaystyle \large{\sum_{n=1}^\infty a_1r^{n-1} = \dfrac{a_1}{1-r}}$

Keep in mind that these only work for when |r| < 1 or else it will diverge.

Also, how fortunately, the given summation fits the formula pattern so we do not have to do anything but simply apply the formula in.

$\displaystyle \large{\sum_{n=1}^\infty 4(0.5)^{n-1} = \dfrac{4}{1-0.5}}\\\\\displaystyle \large{\sum_{n=1}^\infty 4(0.5)^{n-1} = \dfrac{4}{0.5}}\\\\\displaystyle \large{\sum_{n=1}^\infty 4(0.5)^{n-1} = 8}$