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3 years ago

What is the answer to: -2x-y=-9

1 answer:

3 0

Y=9-2x, 9-2x=0, 2x=9, x=9/2, if you were asked to put it in standard form put down the first thing I said, if you were asked for solution then everything I said

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ASAPpppppppppppppppppppppp

Bogdan [553]

Answer:

-4/5

Step-by-step explanation:

2/5 ÷ -1/2

Copy dot flip

2/5 * -2/1

-4/5

8 0

3 years ago

Find the general solution of (x+3)y’=2y

gregori [183]

Answer:

$y=C(x+3)^2$

Step-by-step explanation:

We are given:

$\displaystyle (x+3)y^\prime=2y$

Separation of Variables:

$\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}$

So:

$\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx$

Integrate:

$\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx$

Integrate:

$\displaystyle \ln|y|=2\ln|x+3|+C$

Raise both sides to e:

$|y|=e^{2\ln|x+3|+C}$

Simplify:

$|y|=(e^{\ln|x+3|})^2\cdot e^C$

So:

$|y|=C|x+3|^2$

Simplify:

$y=\pm C(x+3)^2=C(x+3)^2$

5 0

3 years ago

Arun took a taxi from his house to the airport. The taxi company charged a pick-up fee of $4 plus $4.25 per mile. The total fare

Natasha2012 [34]

Here we must write and solve a linear equation to find the number of miles that Arun traveled in the taxi. We will find that Eva traveled 11 miles.

So we know that the taxi charges a fee of $4.10 and then a plus of $0.50 per mile.

So if you travel for m miles, the cost equation is:

C(m) = $4.10 + $0.50*m

Now, we know that for Eva the total fare (total cost) was $9.60, then we need to solve:

$9.60 = C(m) = $4.10 + $0.50*m

$9.60 = $4.10 + $0.50*m

$9.60 - $4.10 = $0.50*m

$5.50 = $0.50*m

$5.50/$0.50 = m = 11

This means that Arun traveled 11 miles in the taxi.

5 0

2 years ago

Can someone plz help me and explain it to me?

Marina86 [1]

You always either divide the equation or multiply the equation
hope this helps

6 0

3 years ago

Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p

PIT_PIT [208]

Answer:

Colin has 8 sheets left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = $x$

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

$\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)$

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

$\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)$

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

$\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8$

So, the answer is:

Colin has 8 sheets left for his third class.

5 0

3 years ago