Answer:
Tn=12n(n+1)
Step-by-step explanation:
Explanation:
These are the triangular numbers - each term in the sequence being the sum of the first n positive integers:
T1=1=1
T2=3=1+2
T3=6=1+2+3
etc.
Notice that:
2Tn=(0)+1+(0)+2+...+(n−1)+(0)+n
2Tn+(0)+n+(n−1)+...+(0)+2+(0)+1
2Tn=(n+1)+(n+1)+...+(n+1)+(n+1)
2Tn=n(n+1)
So:
Tn=12n(n+1)
Answer:
Step-by-step explanation:
6x-1=2x+5+4x-6
separate the variables in one side, numbers on the other side
6x-2x-4x=1+5-6
0=0
one solution
Answer:
huh .
Step-by-step explanation:
Answer:
<h2>b = 4</h2>
Step-by-step explanation:

Answer:

Step-by-step explanation:
Define a cyclic quadrilateral by a quadrilateral that is circumscribed by a circle. In this case, since the quadrilateral shown is circumscribed by a circle, it is a cyclic quadrilateral.
A property of all cyclic quadrilaterals is that their opposite angles are supplementary, meaning they add up to 180 degrees. Since
and
are opposite angles in the quadrilateral, they must be supplementary. Therefore, we have the equation:
