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3 years ago

In the morning, Christopher puts out

Mathematics

1 answer:

melamori03 [73]3 years ago

8 0

Answer:

Step-by-step explanation:

The question didn’t display properly. I’m guessing he puts out 7⅗ pounds in the morning and 6⅘ pounds in the evening.

7⅗ + 6⅘ = 38/5 + 34/5 = 72/5 = 14⅖ pounds

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PLEASE SHOW WORK

CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

$V = \dfrac{\pi}{3}r^2h$

Taking the derivative of V with respect to time, we get

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)$

$\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)$

Since r is always equal to h, we can set

$\dfrac{dr}{dt} = \dfrac{dh}{dt}$

so that our expression for dV/dt becomes

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)$

$\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}$

Solving for dh/dt, we get

$\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}$

$\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})$

$\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}$

7 0

3 years ago

A point is chosen at random in the circle. What percent of the time will the point be in the square?

andreev551 [17]

If te squre is inscribe in the cercle ten:The area of the circle is πR²

& the Area of te square is 2R², then the probability to land in the square :

2R²/πR²=2/π=0.6366 or 63.66%

8 0

3 years ago

37% dextrose solution (37 mg per 100ml of solution) is given iv. Suppose a total of 3.81 liters is given over a 15 hour period.

sashaice [31]

Answer:

During 15 hour period, 1409.7 mg of dextrose will be delivered.

The flow rate of dextrose per hour will be 93.98 mg/hour.

Step-by-step explanation:

If a total of 3.81 liters of the solution is given over a 15 hour period.

Now, 1 liter is equivalent to 1000 ml

So, a total of 3810 ml of the solution is given over a 15 hour period.

If 100 ml of solution contains 37 mg of dextrose, then 3810 ml of the solution will contain $\frac{37 \times 3810}{100} = 1409.7$ mg of dextrose.

So, during the 15 hour period, 1409.7 mg of dextrose will be delivered.

The flow rate of dextrose per hour will be $\frac{1409.7}{15} = 93.98$ mg/hour. (Answer)

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3 years ago

I am a bit confused, can you please help me with #9? :D

lutik1710 [3]

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Oksanka [162]

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