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3 years ago

How to factor a2b2-1 or 144y2-49 can someome help me out on this please

Mathematics

1 answer:

Sonja [21]3 years ago

5 0

A^2b^2-1

The factor of that is (ab-1)(ab+1)

144y^2-49

The factor of that is (12y-7)(12y+7)

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Anyone know the answer?

Aleksandr-060686 [28]

I’m pretty sure it’s d but i’m not 100%

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3 years ago

What is the degree of x^5-4x+2

8090 [49]

Answer:

degree 5

Step-by-step explanation:

the degree of a polynomial is determined by the term with the largest exponent and is the value of the exponent.

$x^{5}$ is the term with the largest exponent of 5

degree of polynomial is 5

8 0

3 years ago

How do you solve this step by step? “ I’m thinking of a number. If you multiply it by 6 and then add 7, you will get 55. What is

lozanna [386]

Answer:

Step-by-step explanation:

55 -7 = 48

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Check answer:

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3 years ago

Read 2 more answers

You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu

aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to $180^{o}$ .

Let the exterior angle be represented by $x^{o}$ , and the three interior angles of the triangle be represented by $a^{o}$ , $b^{o}$ and $c^{o}$ .

Assume that the vertex angle $c^{o}$ is the linear pair to the exterior angle $x^{o}$ .

i.e $x^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles on a straight line)

Thus,

i. $a^{o}$ + $b^{o}$ = $x^{o}$ (sum of two opposite interior angles is equal to an exterior angle)

⇒ $a^{o}$ = $x^{o}$ - $b^{o}$

Also,

$b^{o}$ = $x^{o}$ - $a^{o}$

But,

$a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

⇒ $c^{o}$ = $180^{o}$ - ( $a^{o}$ + $b^{o}$ )

and

$a^{o}$ + $b^{o}$ = $180^{o}$ - $c^{o}$

ii. $a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

$a^{o}$ = $180^{o}$ - ( $b^{o}$ + $c^{o}$ )

Also,

$a^{o}$ + $b^{o}$ = $x^{o}$

⇒ $b^{o}$ = $x^{o}$ - $a^{o}$

$c^{o}$ = $180^{o}$ - $x^{o}$

8 0

2 years ago

If f(x)= x^1/2 - x and g(x)= 2x^3 - x^1/2 - x, find f(x) - g(x)

Pavlova-9 [17]

Answer:

$-2x^3+2x^{1/2}$

Step-by-step explanation:

First, you have to substitute both functions into the equation to get:

$f(x)-g(x) = (x^{1/2}-x) - (2x^3-x^{1/2}-x)$

Then, you distribute the negative sign in front of g(x) to get:

$= x^{1/2} - x -2x^3+x^{1/2}+x$

And finally, you add/subtract the x's that have the same power to get:

$=-2x^3+2x^{1/2}$

3 0

2 years ago