Question

An artist creates a cone shaped sculpture for an art exhibit. If the sculpture is 8 feet tall and has a base with a circumference of 21.352 feet, what is the volume of the sculpture? Use 3.14 for Pi

Answer 1

Answer:

Volume, $V=96.79\ \text{feet}^3$

Step-by-step explanation:

An artist creates a cone shaped sculpture for an art exhibit.

Height of sculpture is 8 feets

The circumference of base of the cone is 21.352 feet.

The base of a con is circular shaped. So,

$2\pi r= 21.352$

r is radius of cone

$r= \dfrac{21.352}{2\times 3.14} \\\\r=3.4\ ft$

The volume of cone shaped sculpture is given by :

$V=\dfrac{1}{3}\pi r^2 h\\\\V=\dfrac{1}{3}\times 3.14\times (3.4)^2 \times 8\\\\V=96.79\ \text{feet}^3$

So, the volume of the sculpture is $96.79\ \text{feet}^3$.