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3 years ago

Y- 4/5=1 what does y equal to?

Mathematics

2 answers:

navik [9.2K]3 years ago

6 0

Answer:

y=1.8

Step-by-step explanation:

first change the fraction into a decimal.

4/5 =0.8

plus the 0.8 to both sides

y=1.8

Vaselesa [24]3 years ago

5 0

Answer:

$y - \frac{4}{5} + \frac{4}{5} = 1 + \frac{4}{5} \\ y = \frac{5 + 4}{5 } \\ y = \frac{9}{5}$

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We know that February has either 28 or 29 days, but there is a year in the future, February will have 30 days

Karo-lina-s [1.5K]

Answer:

The year 2020 is a leap year, which means February will have 29 days rather than 28, and the overall number of days will be 366 rather than 365. This was also the case in 2016, and the year 2024 will be a leap year once more.

Step-by-step explanation:

5 0

3 years ago

Find the value of x

Svet_ta [14]

Answer:

$150^o$

Step-by-step explanation:

Step 1: Distribute the plus

$(x + 15)^o + (135 - x)^o$

$x + 15 + 135 - x$

Step 2: Combine like terms

$x + 15 + 135 - x$

$(x - x)^o + (15 + 135)^o$

$0 + 150^o$

$150^o$

Answer: $150^o$

7 0

3 years ago

Read 2 more answers

Determine the domain and range of each function f(x)=-|x|-2

Alinara [238K]

Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.

Domain: (- infinity, infinity)
Range: (- infinity, -2)

4 0

3 years ago

If <img src="https://tex.z-dn.net/?f=%5Cmathrm%20%7By%20%3D%20%28x%20%2B%20%5Csqrt%7B1%2Bx%5E%7B2%7D%7D%29%5E%7Bm%7D%7D" id="Tex

Harman [31]

Answer:

See below for proof.

Step-by-step explanation:

Given:

$y=\left(x+\sqrt{1+x^2}\right)^m$

First derivative

$\boxed{\begin{minipage}{5.4 cm}\underline{Chain Rule for Differentiation}\\\\If $f(g(x))$ then:\\\\$\dfrac{\text{d}y}{\text{d}x}=f'(g(x))\:g'(x)$\\\end{minipage}}$

$\boxed{\begin{minipage}{5 cm}\underline{Differentiating $x^n$}\\\\If $y=x^n$, then $\dfrac{\text{d}y}{\text{d}x}=xn^{n-1}$\\\end{minipage}}$

$\begin{aligned} y_1=\dfrac{\text{d}y}{\text{d}x} & =m\left(x+\sqrt{1+x^2}\right)^{m-1} \cdot \left(1+\dfrac{2x}{2\sqrt{1+x^2}} \right)\\\\ & =m\left(x+\sqrt{1+x^2}\right)^{m-1} \cdot \left(1+\dfrac{x}{\sqrt{1+x^2}} \right) \\\\ & =m\left(x+\sqrt{1+x^2}\right)^{m-1} \cdot \left(\dfrac{x+\sqrt{1+x^2}}{\sqrt{1+x^2}} \right)\\\\ & = \dfrac{m}{\sqrt{1+x^2}} \cdot \left(x+\sqrt{1+x^2}\right)^{m-1} \cdot \left(x+\sqrt{1+x^2}\right)\\\\ & = \dfrac{m}{\sqrt{1+x^2}}\left(x+\sqrt{1+x^2}\right)^m\end{aligned}$

Second derivative

$\boxed{\begin{minipage}{5.5 cm}\underline{Product Rule for Differentiation}\\\\If $y=uv$ then:\\\\$\dfrac{\text{d}y}{\text{d}x}=u\dfrac{\text{d}v}{\text{d}x}+v\dfrac{\text{d}u}{\text{d}x}$\\\end{minipage}}$

$\textsf{Let }u=\dfrac{m}{\sqrt{1+x^2}}$

$\implies \dfrac{\text{d}u}{\text{d}x}=-\dfrac{mx}{\left(1+x^2\right)^\frac{3}{2}}$

$\textsf{Let }v=\left(x+\sqrt{1+x^2}\right)^m$

$\implies \dfrac{\text{d}v}{\text{d}x}=\dfrac{m}{\sqrt{1+x^2}} \cdot \left(x+\sqrt{1+x^2}\right)^m$

$\begin{aligned}y_2=\dfrac{\text{d}^2y}{\text{d}x^2}&=\dfrac{m}{\sqrt{1+x^2}}\cdot\dfrac{m}{\sqrt{1+x^2}}\cdot\left(x+\sqrt{1+x^2}\right)^m+\left(x+\sqrt{1+x^2}\right)^m\cdot-\dfrac{mx}{\left(1+x^2\right)^\frac{3}{2}}\\\\&=\dfrac{m^2}{1+x^2}\cdot\left(x+\sqrt{1+x^2}\right)^m+\left(x+\sqrt{1+x^2}\right)^m\cdot-\dfrac{mx}{\left(1+x^2\right)\sqrt{1+x^2}}\\\\ &=\left(x+\sqrt{1+x^2}\right)^m\left(\dfrac{m^2}{1+x^2}-\dfrac{mx}{\left(1+x^2\right)\sqrt{1+x^2}}\right)\\\\\end{aligned}$

$= \dfrac{\left(x+\sqrt{1+x^2}\right)^m}{1+x^2}\right)\left(m^2-\dfrac{mx}{\sqrt{1+x^2}}\right)$

Proof

$(x^2+1)y_2+xy_1-m^2y$

$= (x^2+1) \dfrac{\left(x+\sqrt{1+x^2}\right)^m}{1+x^2}\left(m^2-\dfrac{mx}{\sqrt{1+x^2}}\right)+\dfrac{mx}{\sqrt{1+x^2}}\left(x+\sqrt{1+x^2}\right)^m-m^2\left(x+\sqrt{1+x^2\right)^m$

$= \left(x+\sqrt{1+x^2}\right)^m\left(m^2-\dfrac{mx}{\sqrt{1+x^2}}\right)+\dfrac{mx}{\sqrt{1+x^2}}\left(x+\sqrt{1+x^2}\right)^m-m^2\left(x+\sqrt{1+x^2\right)^m$

$= \left(x+\sqrt{1+x^2}\right)^m\left[m^2-\dfrac{mx}{\sqrt{1+x^2}}+\dfrac{mx}{\sqrt{1+x^2}}-m^2\right]$

$= \left(x+\sqrt{1+x^2}\right)^m\left[0]$

$= 0$

8 0

1 year ago

Three people invest at a ratio of 1:4:7. If the partnership is worth $636,000, what did each person invest?

olga_2 [115]

Answer:

See the detailed answers below

Step-by-step explanation:

Given data

Ratio= 1:4:7

combined ratio= 1+4+7= 12

Total amount= $636,000

Apply the part to all method

The first person will take

1/12= x/ 636,000

cross multiply

12x= 636,000*1

x= 636,000/12

x= 53000

The second person will take

4/12= x/ 636,000

cross multiply

12x= 636,000*4

x= 2544000/12

x= 212000

The third person will take

7/12= x/ 636,000

cross multiply

12x= 636,000*7

x= 4452000/12

x= 371000

6 0

3 years ago