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2 years ago

What are all the subsets of the set? {–3, 6}

Mathematics

1 answer:

enyata [817]2 years ago

4 0

b). empty set, {–3}, {6}, {–3, 6}

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(x + 2)4 = x4 + 8x3 +... Use the Binomial Theorem to complete the binomial expansion. Enter only the next three terms; use the ^

larisa86 [58]

(x+2)^4=((x+2)^2)^2(x+2)^2=(x^2+2^2+2(x)(2))= x^2+4+4x (x^2+4+4x)^2=(x^2+4+4x)(x^2+4+4x) = x^4+4x^2+4x^3+4x^2+16+16x+4x^3+16x+16x^2=x^4+4x^3+4x^3+4x^2+16x^2+4x^2+16x+16x+16=x^4+8x^3+24x^232x+16

5 0

2 years ago

What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps. put the answer in units²

AlladinOne [14]

Answer:

Therefore the Area of Rhombus ABCD is 36 unit².

Step-by-step explanation:

Given:

ABCD is a Rhombus

A = (-1,0)

B = (5,-3)

C = (-1,-6)

D = (-7 ,-3)

To Find:

Area of Rhombus ABCD = ?

Solution:

We know that Area of Rhombus is given as

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times d_{1}\times d_{2}$

Where ,

d₁ and d₂ are the Diagonals.

We have,

Diagonals as AC and BD,

Using Distance Formula we get

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting coordinates A and C we get

$l(AC) = \sqrt{((-1-(-1))^{2}+(-6-0)^{2} )}=\sqrt{36}\\l(AC)=6\ unit$

Similarly for BD we have,

$l(BD) = \sqrt{((5-(-7))^{2}+(-3-(-3))^{2} )}=\sqrt{144}\\l(BD)=12\ unit$

Now Substituting AC and BD in Formula we get

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times AC\times BD$

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times 6\times 12=36\ unit^{2}$

Therefore the Area of Rhombus ABCD is 36 unit².

6 0

2 years ago

The steps in writing f(x)=18x+3x2 in vertex form are shown, but a value is missing in the last step. Write the function in stand

Aleks04 [339]

Answer: missing value is 3

Step-by-step explanation:To find the vertex form of parabola given in almost standard form were written following steps:

1. Write the function in standard form:

2. Factor a out of the first two terms:

3. Form a perfect square trinomial:

4. Write the trinomial as a binomial squared:

The vertex is (-3,-27).

6 0

1 year ago

The diameter of a Frisbee is 12 in. What is the area of the Frisbee?

Alina [70]

we know that

Area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius

in this problem

$diameter=12\ in \\ radius=diameter/2\\ radius=12/2\\ radius=6\ in$

$A=3.14* 6^{2}$

$A=113.04 in^{2}$

therefore

the answer is the option

d. 113.04 sq. in.

8 0

2 years ago

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PLEASE ANSWER ASAP!!!!!!! WILL GIVE BRAINLIEST!!!!!!!!

Misha Larkins [42]

Answer:

Based on the data, this is an example of causation.

Step-by-step explanation:

i got it right on the test .

6 0

2 years ago

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