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zepelin [54]
2 years ago
8

Suppose that among all U.S. Students, 80% have gone to an amusement park and 45% have gone to a beach. Only 15% have done neithe

r. If you select a student at random, what is the probability that the student has gone to the beach but not to an amusement park
Mathematics
1 answer:
valentinak56 [21]2 years ago
5 0

Answer:

5%

Step-by-step explanation:

Let x represent the percentage of people that have gone to both the park and the beach.

The percentage of people that have gone only to the amusement park = 80% - x% = 80 - x

The percentage of people that have gone only to the beach = 45% - x% = 45 - x

Therefore:

100% = (80 - x) + (45 - x) + (x) + (15)

100 = 80 + 45 + 15 -x - x + x

100 = 140 - x

x = 140 - 100

x = 40%

Therefore 40% of the students have gone to both the park and the beach.

The probability that the student has gone to the beach but not to an amusement park = 45% - 40% = 5%

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Malia works at a movie theater and is paid hourly. One month, she earned $388.80. The total amount she earns can be found using
AlekseyPX

Answer:

Malia's unit rate is greater than Bill's by $0.05.

Step-by-step explanation:

Consider the provided information.

The total amount she earns can be found using the equation y = 8.1x, where x is the number of hours she works and y is the total amount she earns in dollars.

The unit rate, when written as a fraction, has a denominator equal to one.

The unit price of Malia is $8.1

For Bill works:

Number of hours Total amount earned

18 $144.90

28 $225.40

35 $281.75

Unit price would be:

\begin{gathered}\dfrac{144.90}{18}=\dfrac{y}{x}\\\\8.05=\dfrac{y}{x}\\\\y=8.05x\end{gathered}

18

144.90

=

x

y

8.05=

x

y

y=8.05x

Hence, unit price of Bill is $8.05

Malia's unit rate is 8.1 whereas Bill's unit rate is 8.05,

Thus, Malia's unit rate is greater than Bill's by 8.10-8.05=0.05.

5 0
3 years ago
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Find the GCF (greatest common factor) of 84 and 36. Be sure to show your work. Then, using complete sentences, explain what your
Vsevolod [243]

The answer is 4. By using the factor tree method, you can figure out the GCF of each number. This means 4 is the highest number you can mulitply anything by to get both 84 and 36.

4 0
3 years ago
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Simplified product ?
mel-nik [20]

Answer:

Last choice is correct.

Step-by-step explanation:

\left(\sqrt{10x^4}-x\sqrt{5x^2}\right)\left(2\sqrt{15x^4}+\sqrt{3x^3}\right)

\left(x^2\sqrt{10}-x\cdot x\sqrt{5}\right)\left(2\cdot x^2\sqrt{15}+x\sqrt{3x}\right)

\left(x^2\sqrt{10}-x^2\sqrt{5}\right)\left(2x^2\sqrt{15}+x\sqrt{3x}\right)

x^2\sqrt{10}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)-x^2\sqrt{5}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)

2x^4\sqrt{150}+x^3\sqrt{30x}-2\sqrt{75}x^4-x^3\sqrt{15x}

2x^4\cdot5\sqrt{6}+x^3\sqrt{30x}-2\cdot5\sqrt{3}x^4-x^3\sqrt{15x}

10x^4\sqrt{6}+x^3\sqrt{30x}-10\sqrt{3}x^4-x^3\sqrt{15x}

10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}

Hence final answer is 10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}


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3 years ago
The radius is 20. what's the length of arc AB?
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Step-by-step explanation:

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3 years ago
Help me to answer this pls​
Butoxors [25]

Problem 1

Draw a straight line and plot X anywhere on it.

Use your compass to trace out a circle with radius 1.5 cm. The circle intersects the line at two points. Let's make Y one of those points.

Also from point X, draw a circle of radius 2.5

This second circle will intersect another circle of radius 3.5 and this third circle is centered at point Z.

Check out the diagram below to see what I mean.

=====================================================

Problem 2

Draw a straight line and plot L anywhere on it.

Adjust your compass to 4 cm in width. Draw a circle around point L.

This circle crosses the line at two spots. Focus on one of those spots and call it M.

Draw another circle centered at point M. Keep the radius at 4 cm.

The two circles intersect at two points. Focus on one of the points and call it N.

The last step is to connect L, M and N to form the equilateral triangle.

See the image below.

=====================================================

Problem 3

I'm not sure how to do this using a compass and straightedge. I used GeoGebra to make the figure below instead. It's a free graphing and geometry program which is very useful. I used the same app to make the drawings for problem 1 and problem 2 earlier.

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