We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
Answer:
B) 18 ft
Step-by-step explanation:
The scale is 1 in. model : 6 ft real.
6/1 = 6
To go from model size to real size, multiply the model size by 6 and change from inches to feet.
3 in. model = 3 × 6 ft = 18 ft
Answer:
Answer Below V
Step-by-step explanation:
1. They must be adjacent
2. They have to be connected with the line segment Z
Answer:
a) (2,4)
Step-by-step explanation:
it's where the points meet
Answer:
4) v=kx^2/y^3
2= k(4^2)/(3^3)
2 =k16/27
k = 2(27/16) = 27/8
v = (27/8)(3^2)/(2^3 = (27/8)(9/8) = 243/64
v = 243/64 when x=3 and y=2
Step-by-step explanation:
here
