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grin007 [14]
2 years ago
9

Giving brainless to anyone you can answer the question CORRECT. I’ll also give more points on a next question if you answer it r

ight.

Mathematics
1 answer:
navik [9.2K]2 years ago
7 0

Answer:

1. 104

2. 52

3. 52

Step-by-step explanation:

I think this is right I maybe   be  wrong buthere  is nottees I toooks in 6th

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Help ASAP 1-4 please
s344n2d4d5 [400]
I think that it could possibly be 12 feet but at the same time I'm not sure
6 0
3 years ago
Order the numbers from least to greatest. List the numbers as your final answer. 4, 7, -2, 25, 49, 63, 13, -22, 19, -13, 4/4, 34
sp2606 [1]
-22 , -13, -3, -2 , 4/4, 4, 7, 13, 19, 25, 34, 49, 63
4 0
3 years ago
Read 2 more answers
For a certain​ drug, the rate of reaction in appropriate units is given by Upper R prime (t )equalsStartFraction 2 Over t plus 1
Tems11 [23]

Answer:

a) 8.13

b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)

On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

= 2ln(t+1) + 2(t+1)^1/2 + C

= 2ln(t+1) + 2√(t+1) + C

a) For total reactions from t = 1 to t = 12

When t = 1

R(1) = 2ln2 + 2√2

≈ 4.21

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

When t = 24

R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

3 0
2 years ago
ming-li be spent $15 at the movies. She then earned $30 babysitting. She spent$12 at the bookstore. She now has $18 left. How mu
MrMuchimi

Answer:

$15

Step-by-step explanation:

She began with $15.

3 0
3 years ago
Read 2 more answers
Question 1<br> What is the solution of n² - 49 = 0?<br> 0 +7<br> 07<br> -7<br> O no solution
Sphinxa [80]
Hey there!

This can be written as n^{2}-(7)^{2}

This is in form of \fbox{a^{2}-b^{2}} , it can be expanded as \fbox{(a-b)(a+b)}

=> (n-7)(n+7)=0
=> n -7 = 0 or n + 7 = 0
=> n = 7 or n = -7

So option 7 , -7 are correct.

Hope this is clear :)
Have a good day:)
7 0
1 year ago
Read 2 more answers
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