Answer:
Graph it on a graphing calculator
Step-by-step explanation:
A^2+b^2=c^2 so c^2=12^2+16^2 which then simplifies to c^2=144+256 then simplify that to c^2=400. After that take the square root of c^2 and the square root of 400. So your answer is c=20
<u>Answer:</u>
The amount lost over the 3 years s 2567.25£
<u>Explanation:</u>
![$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$](https://tex.z-dn.net/?f=%24%5Cmathrm%7BF%7D%3D%5Cmathrm%7BI%7D%20%5Ctimes%5Cleft%281-%5Cleft%28%5Cfrac%7Br%7D%7B100%7D%5Cright%29%5Cright%29%5E%7B%5Cmathrm%7Bn%7D%7D%24)
where F = final value after n years
I = initial value of the car in 2017 = £18000 (given)
Since the value is depreciated 5% every year for 3 years,
r = percentage rate of depreciation = 5% (given)
n = 3 years
Substituting these values in formula, we get
![$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$](https://tex.z-dn.net/?f=%24%5Cmathrm%7BF%7D%3D18000%20%5Ctimes%5Cleft%281-%5Cfrac%7B5%7D%7B100%7D%5Cright%29%5E%7B3%7D%24)
=
![$18000 \times\left(\frac{95}{100}\right)^{3}$](https://tex.z-dn.net/?f=%2418000%20%5Ctimes%5Cleft%28%5Cfrac%7B95%7D%7B100%7D%5Cright%29%5E%7B3%7D%24)
= 15432.75£ which is the value of the car after 3 years
Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.
b is the correct answer u got it