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Lunna [17]
3 years ago
11

HELLLPPP me plzz Just help me find the area of this.

Mathematics
2 answers:
Amanda [17]3 years ago
8 0

Answer:10

Step-by-step explanation:

Fed [463]3 years ago
5 0
Answer : 15 count the the inside when doing area
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angle 0 is in quadrant 1 with sin0 = 2/5. Use the Pythagorean identity, sin^2 0 + cos^2 0 = 1, to calculate the value of cos0 as
Gwar [14]
We know that
sin²x+cos²x=1
so 
clear cos x
cos x=(+/-)√[1-sin²x]

in this problem
<span>Angle 0 is in quadrant 1 -----> cos o and sin o are positive
</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5

the answer is
cos o=√21/5

7 0
3 years ago
Pls help! 16 points:)
kenny6666 [7]

Answer: 52 degrees

Step-by-step explanation:

most likley like if correct

7 0
3 years ago
Read 2 more answers
Find an area of a circle​
FrozenT [24]

The area of a circle is pi times the radius squared (A = π r²).

7 0
3 years ago
Solve the equation without the use of a calculator. please Help!!! Thank you!!!<br> 12x^3-30x=5-2x^2
nata0808 [166]

So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:

12x^3+2x^2-30x+5 =0 \implies \\ 2x^2(6x+1)-5(6x+1)=0 \implies \\ (2x^2-5)(6x+1) = 0

Now that we've factored our equation, we can use ZPP and break it up:

2x^2-5 = 0 \implies \\ 2x^2=5 \implies\\ x^2=\frac{5}{2} \implies\\ x=\pm\frac{\sqrt{5}}{\sqrt{2}}=\pm\frac{\sqrt{10}}{2} \\ \\ 6x+1 =0 \implies \\ 6x=-1 \implies\\ x=\frac{-1}{6}

So, our solutions are:

x\in \{\frac{\sqrt{10}}{2},-\frac{\sqrt{10}}{2},-\frac{1}{6}\}

4 0
3 years ago
Subtract 7x^2−5xy+8y2 from −2x^2−15xy+9y^2
Digiron [165]

Answer

Subtract 7x^2 -5xy+8y^2 from -2x^2 -15xy+9y^2

then;

-2x^2 -15xy+9y^2 - (7x^2 -5xy+8y^2)

Remove the bracket we have;

-2x^2 -15xy+9y^2 - 7x^2 + 5xy - 8y^2

Like terms are those terms which have same variable to the same power.

Combine like terms;

-9x^2 -10xy+y^2

Therefore, Subtracting 7x^2 -5xy+8y^2 from -2x^2 -15xy+9y^2 we get -9x^2 -10xy+y^2

7 0
3 years ago
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