<u>QUESTION 2a</u>
We want to find the area of the given right angle triangle.
We use the formula

The height of the triangle is
.
The base is
.
We substitute the given values to obtain,
.
This simplifies to get an expression for the area to be
.
<u>QUESTION 2b</u>
The given diagram is a rectangle.
The area of a rectangle is given by the formula

The length of the rectangle is
and the width of the rectangle is
.
We substitute the values to obtain the area to be

The expression for the area is

<u>QUESTION 2c.</u>
The given diagram is a rectangle.
The area of a rectangle is given by the formula

The length of the rectangle is
and the width of the rectangle is
.
We substitute the values to obtain the area to be

The expression for the area is

<u>QUESTION 2d</u>
The given diagram is a square.
The area of a square is given by,
.
where
is the length of one side.
The expression for the area is

<u>QUESTION 2e</u>
The given diagram is an isosceles triangle.
The area of this triangle can be found using the formula,
.
The height of the triangle is
.
The base of the triangle is
.
The expression for the area is


<u>QUESTION 3a</u>
Perimeter is the distance around the figure.
Let P be the perimeter, then

The expression for the perimeter is

<u>QUESTION 3b</u>
The given figure is a rectangle.
Let P, be the perimeter of the given figure.

This simplifies to

Or

<u>QUESTION 3c</u>
The given figure is a parallelogram.
Perimeter is the distance around the parallelogram

This simplifies to,

Or

<u>QUESTION 3d</u>
The given figure is a rhombus.
The perimeter is the distance around the whole figure.
Let P be the perimeter. Then

This simplifies to,

<u>QUESTION 3e</u>
The given figure is an equilateral triangle.
The perimeter is the distance around this triangle.
Let P be the perimeter, then,

We simplify to get,

QUESTION 3f
The figure is an isosceles triangle so two sides are equal.
We add all the distance around the triangle to find the perimeter.
This implies that,


<u>QUESTION 3g</u>
The given figure is a scalene triangle.
The perimeter is the distance around the given triangle.
Let P be the perimeter. Then

This simplifies to give us,


<u>QUESTION 3h</u>
The given figure is a trapezium.
The perimeter is the distance around the whole trapezium.
Let P be the perimeter.
Then,

We group like terms to get,

We simplify to get,
mm
QUESTION 3i
The figure is an isosceles triangle.
We add all the distance around the figure to obtain the perimeter.
Let
be the perimeter.
Then 
We regroup the terms to get,

This will simplify to give us the expression for the perimeter to be
mm.
QUESTION 4a
The given figure is a square.
The area of a square is given by the formula;

where
is the length of one side of the square.
We substitute this value to obtain;

This simplifies to give the expression of the area to be,

QUESTION 4b
The given figure is a rectangle.
The formula for finding the area of a rectangle is
.
where
is the length of the rectangle and
is the width of the rectangle.
We substitute the values into the formula to get,


QUESTION 4c
The given figure is a rectangle.
The formula for finding the area of a rectangle is
.
where
is the length of the rectangle and
is the width of the rectangle.
We substitute the values into the formula to get,

The expression for the area is

QUESTION 4d
The given figure is a rectangle.
The formula for finding the area of a rectangle is
.
where
is the length of the rectangle and
is the width of the rectangle.
We substitute the values into the formula to get,

The expression for the area is

See attachment for the continuation