For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)
If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9
If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:
1
f(2-h) = ------------------ - 3
4-4h +h^2
I gotchu !! just give me a moment to write it out
Answer:119 4/7
Step-by-step explanation:
2/14+6/14+2/14+4/14+1/14+3/14+4/14= 22/14
10+35+10+12+24+15+12=118
118 22/14
119 8/14
119 4/7
Answer:
x=2
y = 0
Step-by-step explanation:
3x + y = 6 -------------(i)
5x - 2y = 10 -------------(ii)
Multiply (i) by 2 ===> 6x +2y = 12
(ii) ===> <u> 5x - 2y = 10</u>
add ============> 11x = 22
x = 22/11
x = 2
Substitute x = 2 in (i)
3*2 + y = 6
6 + y = 6
y = 6 - 6
y = 0
