Hip Breadths and Aircraft Seats
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. (Accommodating 100% of males would be too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.0 in. Find P 98. That is, find the hip breadth for men that separates the smallest 98% from the largest 2%.
Answer:
x = 6
Step-by-step explanation:
Remark
I'm going to interpret this equation as
D = ut + kt² The only difference is the 2.
Solution
Subtract kt² from both sides.
D - kt² = ut Now divide by u on both sides.
The t's cancel out. on the right. You are left with u on the right.
Answer:
i believe that it is 9(x-4)
Step-by-step explanation:
9x-36
36 divided by 9 = 4
9(x-4)
12.
It is easy all you have to do is 15-3 because 1+2=3
