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salantis [7]
3 years ago
15

GEOMETRY HELP PLEASE!7

Mathematics
1 answer:
Tema [17]3 years ago
7 0

Answer:

<CPE= 137

Step-by-step explanation:

In order to find the measure of (<CPE), one must add the measure of <(CPD) and (<DPE). From the given picture, one can infer that line (CA) is a diameter. This means that the sum of all angles on either side of the line is (180). Therefore, to find the measure of (<DPE) add up all of the angle measures on one side of the line, and set it equal to (180). Solve and then add the result to the value of (<CPD) to find the measure of (<CPE).

(<CPD) + (<DPE) + (<EPA) = 180

Substitute,

88 + (<DPE) + 43 = 180

Simplify,

131 + (<DPE) = 180

Inverse operations,

<DPE = 49

Now add the value of (<DPE) to (<CPD),

(<CPD) + (<DPE)

= 88 + 49

= 137

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How many different committees can be formed from 10 teachers and 37 students of the committee consist of three teachers and two
pashok25 [27]

Answer:

<em>79,920 different ways</em>

Step-by-step explanation:

Combination has to do with selection:

If we are to select 3 teachers from a pool of 10 teachers to form a committee, this can be done in 10C3 number of ways.

10C3 = 10!/(10-3)!3!

10C3 = 10!/7!3!

10C3 = 10*9*8*7!/7!3!

10C3 = 10*9*8/3*2

10C3 = 720/6

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Similarly, selecting five 2 students from a pool of 37 students to form a committee, this can be done in 37C2 difference ways;

37C2 = 37!/(37-2)!2!

37C2 = 37!/35!2!

37C2 = 37*36*35!/35!*2

37C2 = 37*36/2

37C2 = 37 * 18

37C2 = 666 ways

<em>Hence the total number of ways that the 5 committees can be selected is expressed as 10C3 * 37C3 = 120 * 666</em>

<em> 120 * 666 = 79,920 ways</em>

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