Mean of the low is approximately 47.7 Median of the low is 45 and 50 or 47.5
(8c+2a) (4+b) please solve this
1 answer:
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Answer:
The sample size needed is n(if a decimal number, round up to the next integer), considering the estimate of the proportion (if no previous estimate use 0.5) and M is the desired margin of error.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of .
The margin of error is of:
95% confidence level
So , z is the value of Z that has a p-value of
, so
.
Needed sample size:
The needed sample size is n. We have that:
The sample size needed is n(if a decimal number, round up to the next integer), considering the estimate of the proportion (if no previous estimate use 0.5) and M is the desired margin of error.