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timurjin [86]
3 years ago
8

Use the Pythagorean Theorem to solve for x. pls help :(

Mathematics
2 answers:
densk [106]3 years ago
8 0

Answer:

5 in

Step-by-step explanation:

13^2-12^2=25, the square root of 25 is 5

Kruka [31]3 years ago
4 0

Answer:

5

Step-by-step explanation:

a squared + b squared = c squared

144 + b^ = 169

169-144=25

square root of 25 = 5

hope this helps:)

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solve this problem so the hiking trails in roman nose park are 3.6, 7.9, 10.4, 5.7, and 3.5 miles long. Cindy and Geoff hiked tw
DENIUS [597]
Your answer is c 3.6 and 5.7 miles

6 0
3 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
Evaluate 5 c - 3 d+11 when c= 7 and d= 8
kotykmax [81]
5x7-3x8+11
35-24+11
11+11
The answer is 22
8 0
3 years ago
Read 2 more answers
PLS ANSWER QUICK The science center has 200 people in attendance on Monday. The center expects Saturday’s attendance to be 140 p
Rzqust [24]

Answer:

solution

100%=200

140%=?

=280

4 0
3 years ago
please help me!!!!!!!!!!!!!
yKpoI14uk [10]
Let x be the length of each row.
Denver can plant 3 rows of a certain length with 2 seedlings leftover.
Total number of seeds he has = 3x+2 Denver can plant 4 rows of the same length with 3 seedling spots left empty.
Total number of seeds he has = 4x-3 Using (i) and (ii), we get= 3x+2=4x-3

Isolate variable terms: 2+3=4x-3
Answer= 5=X
5 0
3 years ago
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