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Ganezh [65]
2 years ago
9

The height of a golf ball, in meters, x seconds after it has been hit is given by the expression -4.9x^(2) +4.8x+0.1 . When does

the ball hit the ground?
Mathematics
2 answers:
iragen [17]2 years ago
7 0

Answer:

t = 1 second

Step-by-step explanation:

The height of a golf ball, in meters, x seconds after it has been hit is given by the expression.

h=-4.9x^2 +4.8x+0.1

We need to find the time when the ball will hit the ground.

When it hits the ground, h=0

-4.9x^2 +4.8x+0.1=0

It is a quadratic equation. The solution of the above equation is :

x = 1 seconds, x = -0.02 seconds

Hence, after 1 second the ball will hit the ground.

Wewaii [24]2 years ago
7 0

Answer:

t=1

Step-by-step explanation:

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Mario went to a store and bought 3 slices of pizza. The guy at the register said " that would be $3.75". Mario then said "wait,
Zarrin [17]

Answer:

$5

Step-by-step explanation:

Cost per slice

3.75 / 3 = 1.25

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3 years ago
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Delvig [45]

Answer:

$10

Step-by-step explanation

Liam has $10 left for himself. Simply divide $240 by the 24 kids and you get $10 as your total. Thsi is what I could get as the answer since the price of the gift was'nt included.

4 0
3 years ago
The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac
olya-2409 [2.1K]

Answer:

a) \frac{74}{10025}

b) \frac{3x-2}{x(8x+1)}

c) \frac{-24x^2+32x-2}{(8x^2+x)^2}

Step-by-step explanation:

For total cost function c(x), average cost is given by \frac{c(x)}{x} i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., \left ( \frac{c(x)}{x} \right )'

Given:c(x)=\frac{3x-2}{8x+1}

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

a)

At x = 50 units,

\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}

b)

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

c)

Marginal average cost:

Differentiate average cost with respect to x

Take f=3x-2\,,\,g=8x^2+x

using quotient rule, \left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}

Therefore,

\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}

3 0
3 years ago
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Valentin [98]

Answer: (a) e ^ -3x (b)e^-3x

Step-by-step explanation:

I suggest the equation is:

d/dx[integral (e^-3t) dt

First we integrate e^-3tdt

Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.

(b) to differentiate the integral let x = t, and substitute into the expression.

Therefore dx = dt

Hence, d/dx[integral (e ^-3x dx)] = e^-3x

8 0
3 years ago
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I really need help with this question please someone help me
Radda [10]

\mathrm{Inverse\:of}\:\frac{7}{x}-9:\quad \frac{7}{x+9}

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4 0
3 years ago
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