Answer:
This is a weird one but d=443/24
Step-by-step explanation:
Answer:
D
Step-by-step explanation: (i know this part. its the graph im a tiny bit unsure about)
x
__ y
2 __2
3 __ 2.387
7__
3
Answer:
40 drops
Approximately 0.166 %
Step-by-step explanation:
It would be easier to work the same units for volume
Since there are 1000 ml in a liter
Original water volume 1.2 L = 1.2 x 1000 = 1200 mLl
The final volume of the acid-water solution = 1.202 L = 1202 mL
So total volume of acid added = 1202-1200 = 2 mL
Each drop of acid is 0.05 mL
Number of drops added = 2/.05 = 40 drops
Percent of acid in acid solution = (Volume of acid added)/(Final volume) x 100 = (2/1202) ≈ 0.00166 x 100 ≈ 0.166 %
You want to find the area left over after the pool is built, so subtract the area of the pool from the area of the yard.
Area of Yard= Base x Height = 14x*19x = 266x^2
Area of Circle= Pi x Radius^2 = (6x)^2*pi = 36x^2*pi
Now subtract the two areas:
266x^2-(36^2*pi)
266x^2-36x^2*pi
Take 2x^2 as a common factor:
2x^2(133-18pi)
D: <span>2x^2(133-18pi)
Hope this helps :)</span>
