Answer:
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
Any smooth curve connecting two points is called an arc. The length of the arc m∠QPR is 2.8334π m.
<h3>What is the Length of an Arc?</h3>
Any smooth curve connecting two points is called an arc. The arc length is the measurement of how long an arc is. The length of an arc is given by the formula,

where
θ is the angle, that which arc creates at the centre of the circle in degree.
Given the radius of the circle is 3m, while the angle made by the arc at the centre of the circle is 170°. Therefore,
The length of an arc = 2πr×(θ/360°) = 2π × 3 ×(170/360°) = 2.8334π m
Hence, the length of the arc m∠QPR is 2.8334π m.
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Simply substitute the point into the given equation; as there is one variable, you only need one point and so one is given. When done so, you shall get b=4