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marusya05 [52]
3 years ago
9

What points are solutions to the linear equality graph? Select all that apply.

Mathematics
1 answer:
Ahat [919]3 years ago
6 0
I think it’s B, C and E because they’re on the shaded region
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How do I solve this problem ?4x+7y=42 when X=9
Rufina [12.5K]
First you would plug in the 9 for x, then you would try to solve for y
5 0
4 years ago
Read 2 more answers
In the fraction 15⁄7, which of the following is 15? Numerator Divisor Denominator Factor
Colt1911 [192]

Answer is Numerator.

In a fraction, the denominator is on the bottom and the numerator is on top. A factor is a number, when multiplied with another number, that equals the final product. For example: 1, 2, 3, 6, 9, 18 are all factors of 18. A divisor is something you are dividing by in a division problem.

3 0
3 years ago
Drag the phrases into the box to match each expression. 3/4x+1/2 ​ 3/4−1/2x ​ ​ 3/4−(x+1/2) ​ 20 pointss!!! i know i must be cra
fomenos

Answer:

\frac{3}{4}x + \frac{1}{2} = One-half more than three-fourths of a number

\frac{3}{4}-\frac{1}{2}x = Three-fourths minus one-half of a number

\frac{3}{4}-(x+\frac{1}{2}) = three-fourths minus the sum of a number and one-half

Step-by-step explanation:

Suppose x be an unknown number.

∵ 3/4th of a number = \frac{3}{4}x

\frac{3}{4}x + \frac{1}{2} = One-half more than three-fourths of a number

Now, half of a number = \frac{1}{2}x

\frac{3}{4}-\frac{1}{2}x = Three-fourths minus one-half of a number

Sum of a number and one-half = x+\frac{1}{2}

\frac{3}{4}-(x+\frac{1}{2}) = three-fourths minus the sum of a number and one-half

6 0
3 years ago
Help please word problem...show work please
Alona [7]
A) you must plug in 50 for variable F and solve for C

C=\frac{5}{9}(50-32)
C=\frac{5}{9}(18)
C= 10
50 degrees fahrenheit is equal to 10 degrees celsius 

B) you must solve the equation for F

C= \frac{5}{9}(F-32)
C/\frac{5}{9}=F-32
C/\frac{5}{9}+32=F
F= C/\frac{5}{9}+32

dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as

F=\frac{9}{5}C +32

now you just plug in 50 for the variable C in the new equation

F= \frac{9}{5}(50) +32
F= 90 + 32
F= 122

50 degrees celsius is equal to 122 degrees fahrenheit

hope this helped!

6 0
3 years ago
Simplify and solve for the unknown. Use order of operations as needed.<br>8×2+5^2-y=2(y+1)+6 ​
Ket [755]

Answer:

y = 11

Step-by-step explanation:

8 × 2 + 5²- y = 2(y + 1) + 6 ​

8 × 2 + 5²- y = 2y + 2 + 6 ​

8 × 2 + 25 - y = 2y + 2 + 6 ​

16 + 25 - y = 2y + 2 + 6

41 - y = 2y + 8

41 (- y + y) = (2y + y) + 8

41 = 3y + 8

41 - 8 = 3y (+ 8 - 8)

33 = 3y

33/3 = 3y/3

y = 11

3 0
3 years ago
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