Soaring Eagles Corp. has total current assets
1 answer:
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Answer with Step-by-step explanation:
We are given that
for
We have to prove that for all n equal and greater than 1
proof: Let P(n)= for all n equals to and greater than 1
We prove that for all n there exists Z,if n greater and equals to zero
Base case : The base case is n=1
Substitute n=1 then we get
P(1)=-3(1)+5=2
This is true for n=1
Induction step : suppose that P(n) is true for n=k where k greater than 1
Then P(k)=-3k+5
Now, we shall prove that for n=k+1, P(n) is true for n=k+1
P(k+1)=-3(k+1)+5
P(k+1)=-3k-3+5=-3k+5-3
We are given that for n equal to and greater than 2
Therefore, P(n) is true for n=k+1
Hence, P(n)=-3n+5 for all n equal and greater than 1