Answer:
- h = 0 when the ball hits the ground
- about 3.464 seconds
Step-by-step explanation:
The formula gives h = 192 when t=0, so we assume that h represents the height above the ground. The ball will have a height of 0 when it hits the ground.
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Using that in the equation, we can solve for t.
0 = 192 -16t^2
0 = 12 -t^2 . . . . . . divide by 16
t^2 = 12 . . . . . . . . add t^2
t = √12 = 2√3 ≈ 3.464 . . . . take the square root
It will take 2√3 seconds, about 3.464 seconds, for the ball to hit the ground.
Step-by-step explanation:
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Answer:
That should be it if I'm not mistaken. The first one is y= 4+x, and the second one is y= 2x
Step-by-step explanation:
Can I get Brainliest if I'm right?
You multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get 3x^2y
1)
Break up the irregular shape into two rectangles
12 * 4.5 = 54
2 * 5 = 10
54 + 10 = 64 cm^2
2)
Break up the irregular shape into a triangle and rectangle
24 * 8 = 192
To get the base of the triangle:
24 - 6 - 6 = 12
To get the height of the triangle:
16 - 8 = 8
1/2(12 * 8) = 48
192 + 48 = 240 yd^2
3)
Separate into triangle and semi circle
To get the base: 8 * 2 = 16
1/2(15 * 16) = 120
(pi (8)^2)/2 = 100.5
120 + 100.5 = 220.5 cm^2
4)
Separate half circle from rectangle
(pi (7.5)^2)/2 = 88.4
7 * 15 = 105
88.4 + 105 = 193.4 m^2
5)
Separate triangle from trapezoid
2.8 * 7 = 19.6
(7+9/2)(3.6) = 28.8
19.6 + 28.8 = 48.4 ft^2
6)
Separate semi circle from trapezoid
(pi(3)^2)/2 = 6.3
(6+10/2)(8) = 64
6.3 + 64 = 70.3 yd^2
