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KengaRu [80]
3 years ago
11

7. Which transformation is not an isometry?

Mathematics
1 answer:
Neko [114]3 years ago
5 0
<h3>Answer: Choice B</h3>

Explanation:

Choice A is a reflection. Choice C is a rotation. Reflections and rotations are isometries because they preserve the same shape and size of the original figure. Translations are the third type of isometry.

Choice B is not an isometry. It looks like an extra point is added along with extra line segments. The before and after figures are completely different.

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Pls HAAAAAAAALLLLPPPPP plez
Virty [35]

Answer:

The correct answer is F. x = 50

Step-by-step explanation:

Since angle PQR and angle TQV are vertical angles, it means their values will be equal. And since the two angles have a sum of 100°, their measure will be equal.

Therefore, the measure and value of angle TQV will be 50°.

5 0
3 years ago
A. Tape diagram A
Serjik [45]

Answer:

x=6

Step-by-step explanation:

7 0
3 years ago
Find The value of X to the nearest tenth<br> A 7.0<br> B 4.7<br> C 5.7<br> D 8.2
vredina [299]
Here is the correct answer, and explanation for how to get the answer, and a way to remember how to use them for next time :)

3 0
3 years ago
4.4 + (4 × 14 + 8.6)
Sedaia [141]

4.4 + (4 × 14 + 8.6)

Follow the order of operations (PEMDAS).

4.4+(56+8.6)

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6 0
3 years ago
Read 2 more answers
Find each product.<br><br> 1. 2x(x^2-6x+3)<br><br> 2. 2a^2(5b^2 + 3ab + 6a + 1)
hoa [83]

Given:

The expressions are:

2x(x^2-6x+3)

2a^2(5b^2+3ab+6a+1)

To find:

The product of each expression.

Solution:

According to the distributive property of multiplication over addition, we get

a(b+c)=ab+ac

The first expression is:

2x(x^2-6x+3)

Using distributive property of multiplication over addition, we get

2x(x^2-6x+3)=(2x)(x^2)+(2x)(-6x)+(2x)(3)

2x(x^2-6x+3)=2x^3-12x^2+6x

Therefore, the product of 2x(x^2-6x+3) is 2x^3-12x^2+6x.

The second expression is:

2a^2(5b^2+3ab+6a+1)

Using distributive property of multiplication over addition, we get

2a^2(5b^2+3ab+6a+1)=(2a^2)(5b^2)+(2a^2)(3ab)+(2a^2)(6a)+(2a^2)(1)

2a^2(5b^2+3ab+6a+1)=10a^2b^2+6a^3b+12a^3+2a^2

Therefore, the product of 2a^2(5b^2+3ab+6a+1) is 10a^2b^2+6a^3b+12a^3+2a^2.

3 0
3 years ago
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