(3.78x109)<span>÷14,000
=0.02943
= 2.943 x 10^-2</span>
Answer:
See below
Step-by-step explanation:
From noon to 1500 is three hours
train A then travels <u> 3x</u> where x = speed in km/hr
train B only travels for 2.45 hours and covers
<u> 2.45 ( x + 15) </u> where x + 15 is its speed in km/hr
these two values sum to the 300 km distance
3x + 2.45 ( x + 15) = 300
3x + 2.45 x + 36.75 = 300
x = 48.3 km/hr x+15= 63.3 km / hr
The answer is f(x) = 3/2(3/2)^x. Hope this helps
