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3 years ago

F(x)=bx^2+32 For the function f defined above, b is a constant and f(2)=40. What is the value of f(-2)?

Mathematics

2 answers:

zhuklara [117]3 years ago

6 0

Answer:

f(-2) = 0

Step-by-step explanation:

Given that:

f(x) = bx^2 + 32

f(2) = b(2)^2 + 32

f(2) = 4b + 32

f(2) = 4b = -32

f(2) = b = -32/4

f(2) = b = -8

Thus;

f(-2) = -8(-2)^2 + 32

f(-2) = -8(4) + 32

f(-2) = -32 + 32

f(-2) = 0

Vitek1552 [10]3 years ago

4 0

Answer:C

Step-by-step explanation:

yessir

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Step-by-step explanation:

Given:

sequences: $-1,4,-7,10,...$

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