F(x)=bx^2+32 For the function f defined above, b is a constant and f(2)=40. What is the value of f(-2)?
2 answers:
Answer:
f(-2) = 0
Step-by-step explanation:
Given that:
f(x) = bx^2 + 32
f(2) = b(2)^2 + 32
f(2) = 4b + 32
f(2) = 4b = -32
f(2) = b = -32/4
f(2) = b = -8
Thus;
f(-2) = -8(-2)^2 + 32
f(-2) = -8(4) + 32
f(-2) = -32 + 32
f(-2) = 0
Answer:C
Step-by-step explanation:
yessir
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