13.) The leading scorer in your high school's hockey league finished the season with an average of 4 goals per game for 15 games
. As the leagues
second leading scorer, you have an average of 4 goals per game for 14 games. You still have to play your last game. How many goals must you
score in the final game to overtake the leagues' leading scorer?
second leading scorer, you have an average of 4 goals per game for 14 games. You still have to play your last game. How many goals must you
score in the final game to overtake the leagues' leading scorer?
1 answer:
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The correct option is 20.
The score found for the sample is 20.
<h3>What is Standard error?</h3>A standard error is a statistic that is applied to test the distribution of data. This metric is comparable to standard deviation. We can calculate the standard error if we know the sample size & standard deviation. It assesses the mean's precision.
Now, according to the question;
Sample mean;
Sample variance;
Thus,
Standard error SE = 1
The amount of scores with in sample must be determined here.
The standard error formula is as follows:
We might rearrange the formula as follows:
Substituting the values;
The sample's number of scores n = 19.98 = 20 (round up)
Therefore, the scores are in the sample is 20.
To know more about the Standard error, here
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The value of f(a)=4-2a+6, f(a+h) is
, [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6
.
Given a function f(x)=4-2x+6.
We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.
Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.
f(a)=4-2a+6 (By just putting x=a).
f(a+h)==
=4-2a-2h+6()
=4-2a-2h+6
=
[f(a+h)-f(a)]/h=[-(4-2a+6
)]/h
=
=
=6h+12a-2.
Hence the value of function f(a)=4-2a+6, f(a+h) is
, [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6
.
Learn more about function at brainly.com/question/10439235
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