I need help with completing the reasons for the proof. The first 3 statments are given.
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
Total possibilities when we a roll a die at a time are 6
given we should have four for first time and then three
let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is
PROBABILITY=
Favourable chances=1
Total chances=6
Probability=
the prabability to get 4 in first roll is .
let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is
Favourable chances=1
total chances=6
probability=
the probability to get 3 in second roll irrespective of first one is
the probability to get 4 in first time and then 3 is
The probability to occur both events at a time is multiplication of individual probabilities
So,
probablility to get 4 in first roll=
probability to get 3 in second roll=
probability to occur both at a same time is =
=