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inn [45]
3 years ago
15

A rectangular garden has a perimeter of 50cm. The length of one side is 15cm. What is the measurement of the width?​

Mathematics
1 answer:
sineoko [7]3 years ago
5 0

Answer:

The measurement of the width is 10cm.

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Sara is a big hip-hop music fan. Her friend Matt is a big rap music fan. They each have a huge library of songs in their digital
Orlov [11]

The critical value is 1.99 and the null hypotheses is μ - μ₂ = 0 and alternative hypotheses for this test is μ - μ₂ ≠ 0.

According to the statement

we have given that the sample of songs is 50. and the average of hip hop is μ₂.

For this purpose, we know that the

Sara and matt would like to know if the average length of the hip hop songs say μ₁ differ from the average of the hip hop songs say μ₂. It means μ₁ ≠ μ₂.

so, The null and alternative hypothesis value are:

H(null) = μ - μ₂ = 0 And

H (alternative) = μ - μ₂ ≠ 0.

From this it is clear that the this the value of hypothesis.

So,

Now, Let the degree of freedom be a x.

Then

At \alpha = 0.05 then the value of k is 80,.

Then the critical value is

t = (\frac{\alpha }{2} , k) = 1.99

Here the critical vale is 1.99.

So, The critical value is 1.99 and the null hypotheses is μ - μ₂ = 0 and alternative hypotheses for this test is μ - μ₂ ≠ 0.

Learn more about null and alternative hypothesis here

brainly.com/question/15980493

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Sara is a big hip-hop music fan. Her friend Matt is a big rap music fan. They each have a huge library of songs in their digital music libraries. They each randomly sample 50 songs from their libraries and record the lengths of the songs selected. The average of the selected hip hop songs was *, - 245 seconds with a sample standard deviation of 5 seconds. The average of the selected rap songs was X - 275 seconds with a sample standard deviation of 6 seconds. They would like to know if the average length of hip-hop songs is different than the average length of rap songs. (a) What are the appropriate null and alternative hypotheses for this test? (b) Assume for purposes of this study, the degrees of freedom are 80. At a 5% significance level, what is the critical value for the test?

#SPJ4

8 0
2 years ago
A, B, and C are points of tangency. CQ = 5, PQ = 10, and PR = 14. What is the perimeter
igomit [66]

*see attachment for diagram

Answer:

Perimeter = 38

Step-by-step explanation:

Recall: when two tangents are drawn to meet at a point outside a circle, the segments of the two tangents are congruent.

Given,

CQ = 5

PQ = 10

PR = 14

Perimeter of ∆PQR = RC + CQ + QB + BP + PA + AR

CQ = QB = 5 (tangents drawn from an external point)

BP = PQ - QB

BP = 10 - 5 = 5

BP = PA = 5 (tangents drawn from an external point)

AR = PR - PA

AR = 14 - 5 = 9

AR = RC = 9 (tangents drawn from an external point)

✔️Perimeter of ∆PQR = RC + CQ + QB + BP + PA + AR

= 9 + 5 + 5 + 5 + 5 + 9

Perimeter = 38

7 0
3 years ago
Determine the rate of change for the graph from 2010 to 2012​
mash [69]

Answer:

B)-20 students per year

8 0
3 years ago
Given the function how do I solve
BARSIC [14]

Answer: (a) -7      (b) \bold{\dfrac{4}{25}}      (c) \bold{-\dfrac{5}{2}}    (d) 4

Step-by-step explanation:

A) f(x) = 2x - 3      when x is between -5 and -2 (including -5 and -2)

B) f(x) = x²            when x is between -2 and 2 (including 2)

C) f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}             when x is between 2 and 5 (including 5)

a) Equation A includes x = -2

   f(x) = 2x - 3

   f(-2) = 2(-2) - 3

           =  -4    - 3

           =       -7

b) Equation B includes x = -\dfrac{2}{5}

   f(x) = x²

   f\bigg(-\dfrac{2}{5}\bigg) = \bigg(-\dfrac{2}{5}\bigg)^2

        =\dfrac{4}{25}

c) Equation C includes x = 4

   f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}

   f(4)=-\dfrac{3}{2}(4)+\dfrac{7}{2}

       =-\dfrac{12}{2}+\dfrac{7}{2}

       =-\dfrac{5}{2}

d) Try each equation to see if x falls within the values given.

A) f(x) = 2x - 3

   -2.5 = 2x - 3

    0.5 = 2x

  0.25 = x    NOT VALID since x should be between -5 and -2

B) f(x) = x²

   -2.5 = x²

   \sqrt{-2.5}=x  NOT VALID since x cannot be an imaginary number

C) f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}

    -\dfrac{5}{2}=-\dfrac{3}{2}x+\dfrac{7}{2}

    -\dfrac{12}{2}=-\dfrac{3}{2}x

    -\dfrac{12}{2}\bigg(\dfrac{2}{3}\bigg)=x

    4 = x        VALID since x is between 2 and 5

5 0
4 years ago
A man dropped his keys into the sea and watched them fall to a depth of −8 meters before landing on a rock. How far are the keys
Lena [83]

Answer:

8 meters

Step-by-step explanation:

Use absolute value to figure this out.

please mark me brainliest!

3 0
4 years ago
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