Solving equations using Zero-Product property

Mathematics

2 answers:

FrozenT [24]3 years ago

7 0

Answer:if y=0

Step-by-step explanation: view y as 0, so you have 2*0*(-8+0+7)=0

every number multiplied by 0 is 0 so 2*0 is 0 then in the brackets you will have -1. So the final line is 0*-1=0 like I said every number multiplied for 0 is 0 the equation is true for y=0

Lady bird [3.3K]3 years ago

7 0

Answer:

see explanation

Step-by-step explanation:

The zero product property applies to the product of factors equal to zero

For example

a × b = 0

Since the product of the 2 numbers is zero , then one of the numbers must be zero, that is

a = 0 or b = 0

This can be applied to the product

2y(- 8y + 7) = 0

The 2 values being multiplied are 2y and (- 8y + 7)

Thus one or the other must equal zero, so solve both

2y = 0 ⇒ y = 0, or

- 8y + 7 = 0 ⇒ - 8y = - 7 ⇒ y = $\frac{-7}{-8}$ = $\frac{7}{8}$

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When 1 is subtracted from three- tenths of the number, the result is equal to one-fifth of a number. What is the number

Bas_tet [7]

Based on the given mathematical statement, it can be rewritten into a mathematical equation to simplify and to be solved easily. The statement, "When one is subtracted from three-tenths of a number" corresponds to the equation, 3x/10 - 1, that is assuming the number is represented by the variable x. This is equal to one-fifth of the number. In other words,
3x/10 - 1 = x/5
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8 0

3 years ago

Define fn : [0,1] --> R by the

sasho [114]

Answer:

The sequence of functions $\{x^{n}\}_{n\in \mathbb{N}}$ converges to the function

$f(x)=\begin{cases}0&0\leq x$ .

Step-by-step explanation:

The limit $\lim_{n\to \infty }c^{n}$ exists and converges to zero whenever $\lvert c \rvert$ . But, if $c=1$ the sequence $\{c^{n}\}$ is constant and all its terms are equal to $1$ , then converges to $1$ . Using this result, consider the sequence of functions $\{f_{n}\}$ defined on the interval $[0,1]$ by $f_{n}(x)=x^{n}$ . Then, for all $0\leq x$ we have that $\lim_{n\to \infty}x^{n}=0$ . Now, if $x=1$ , then $\lim_{n\to \infty }x^{n}=1$ . Therefore, the limit function of the sequence of functions is