Answer:
169.41 mi
Step-by-step explanation:
Let the time required for the outbound trip be t1 and that for the inbound (return) trip be t2. Then t1 + t2 = 4 hr. We can eliminate one variable by solving this equation for it: t1 = 4h - t2.
Then the time spent on the outbound trip was t1 = d / (40 mph) and that on the inbound trip t2 = d / (45 mph). We want to find the total distance traveled, which will be 2d.
d d
t1 + t2 = 4 hr becomes ---------------- + --------------- = 4 hr
40 mph 45mph
We must solve for d. The LCD here is 40*45, or 1800; thus, this equation becomes
45d + 40d = 4(1800), or 85d = 7200. Thus, d = 84.7 miles.
Michael drives this same distance going and returning, so the total distance he drives is 2(84.7 miles) = 169.41 mi
615.44 = (3.14)(radius)^2
<span>radius = square-root of (615.44/3.14) </span>
<span>diameter = radius x 2 </span>
<span>diameter = 28 inches
3.14
</span>
Answer:
x= -7/5 y=8/5
Step-by-step explanation:
1. choose a variable to eliminate (i chose 6)
2. multiply the first equation by 2 and the second equation by 3
3. now you have
-6x+6y=18
6x-21y=-42
and the x's can now cancel out when you add the equations together
4. after adding the equations, you get
-15y=-24
5. solve for y (y= 8/5)
6. now plug in 8/5 for the y in one of the original equations to solve for x. (i chose the first one)
7. -3x+3(8/5)=9
-3x+24/5=9
-3x=21/5
x= -7/5
The answer is the first 1 !!
Here is how we see if it is true!
If Clayton drives 60 miles per hour, that means, <u>t</u>hat after one hour has passed, they should have traveled 60 miles!
If we look at the number of hours that have passed between 1:30 and 4:30, it is 3 hours.
If someone travels 60 miles every hour that has passed, and they traveled for 3 hours. To find how far they have traveled we just need to multiply 60 miles by 3 hours!
Let's solve that!
60 × 3 = 180 miles!
Clayton started driving at 1:30 pm and went 60 miles per hour.
25 - 6r = 25
-6r = 25-25
-6r = 0
r = 0/-6
r = 0