Answer:
Since the question is partial, i will assume 2 scenarios:
They need to raise 1000 income
They need to make 1000 as profit
If $1000 as income:
Each ticket costs $15, so tickets would bring them $1000 income. Fractional ticket is not possible, so rounding gives us 67 tickets as the answer.
If $1000 as profit:
Their cost of renting is $700. We know that .
So, . So, to raise $1700, we need tickets. Fractional ticket is not possible, so rounding gives us 114 tickets as the answer.
ANSWER:
If need to raise atleast $1000 as income, they need to sell 67 tickets.
If need to raise atleast $1000 as profit, they need to sell 114 tickets.
The most probable answer would be 114 tickets
PLZ MARK ME BRAINLIEST
Answer:
b/a
Step-by-step explanation:
Given,(b^-2)/a*(b^-3)
or,(b^-2+3)/a
or,b/a
You just divide the 3.60 by the eight and then you get 45 cents for each box.
Answer: 31 mint plants
Step-by-step explanation:
We will have mint plants over total plants:
29/29+29 = 29/58 = 1/2
Now, we will multiply 62 by 1/2 to guess how many mint plants will be stocked.
62* 1/2 = 31
We should expect about 31 plants of the total plants to be mint plants.
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±)/2. So, PQ=, PQ²=. Thus, the answer is 61+4=65.
Step-by-step explanation: