Complete Question
Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.
Answer:
The 90% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of people that watched the educational television is 
Generally the sample proportion is mathematically represented as

=> 
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
Answer:
its 6
Step-by-step explanation:
i calculated but threw in trash by an accident
Answer:
(a) Stops, turns around and starts travelling back towards home.
(b) 8 km/hour.
Step-by-step explanation:
(b) Jo travels 4 kilometres in 1/2 hour = 9 km/hour.
Would it be
1) -4.25
2) -5 1/4
3) -1/2
4) -2 1/3
5) 3.85
6) 6.1
I think its b, i hope this is the rigth answer this was a little tough...