What is the slope of the line that passes through the points (-3,-9) and (22,-4)

What is the value of the expression 2x2+3xy-y2, when x=2 And y=-4

Otrada [13]

Plug in 2 for x, and -4 for y

2(2)² + 3(2)(-4) - (-4)²

2² = 4(2) = 8
3(2) = 6(-4) = -24
-4² = 16

8 - 24 - 16 = answer

Simplify.

answer = 8 - 40
answer = -32

-32 is your answer

hope this helps

7 0

2 years ago

What is the product?

Gnoma [55]

The correct product of (6x - 2)(6 x + 2) is 36x^2 - 4

<h3>How to determine the product?</h3>

The expression is given as:

(6x - 2)(6 x + 2).

The above expression is a difference of two squares.

And this is represented as

(a - b)(a + b)= a^2 - b^2

So, we have

(6x - 2)(6 x + 2) = (6x)^2 - 2^2

Evaluate

(6x - 2)(6 x + 2) = 36x^2 - 4

Hence, the correct product of (6x - 2)(6 x + 2) is 36x^2 - 4

Read more about difference of two squares at:

brainly.com/question/3189867

#SPJ1

<u>Complete question</u>

What is the product?

(6x - 2)(6 x + 2).

6 0

1 year ago

a 2 1/2m board is to be used for making shelves,each using up 5/6m of board. Does he have enough board left to make another shel

Hunter-Best [27]

I dont think so because if you multiply 2 1/2 by 5/6 you would get 2 1/12 which means that you can make the first shelf but you would need to subtract 2 1/2 minus 2 1/12 and you would get 5/12. And 5/12 is not the same as 4/5

Hope this helps!!! Name me brainliest please!

6 0

3 years ago

Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A

alekssr [168]

Answer:

$\theta_{CAB}=128.316$

$\theta_{ABC}=25.842$

$\theta_{BCA}=25.842$

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

$r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

$AB= \sqrt{(-3-1)^2+(0-3)^2}=5$

$BC= \sqrt{(1-1)^2+(3-(-3))^2}=9$

$CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5$

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

$BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}$

$\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}$

$\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}$

$\theta_{CAB}=\arccos{-\dfrac{0.62}}$

$\theta_{CAB}=128.316$

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

$\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}$

$\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)$

$\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)$

$\theta_{ABC}=\arcsin{0.4359}\right)$

$\theta_{ABC}=25.842$

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

$\theta_{BCA}=25.842$

this can also be checked using the fact the sum of all angles inside a triangle is 180

$\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180$

$25.842+128.316+25.842$

$180$

6 0

2 years ago

Read 2 more answers

If T equals 1 / r + 1 / s equals r + S over RS, then what is 1 / T in terms of R&S?

Thepotemich [5.8K]

$T=\dfrac{1}{r}+\dfrac{1}{s}\\\\T=\dfrac{1\cdot s}{r\cdor s}+\dfrac{1\cdot r}{r\cdot s}\\\\T=\dfrac{s}{rs}+\dfrac{r}{rs}\\\\T=\dfrac{s+r}{rs}\to\dfrac{1}{T}=\dfrac{rs}{s+r}$

7 0

3 years ago