Question

** NEED HELPPPP **

Answer 1

Answer: The answer is 48 cows.

Step-by-step explanation: Given that a farmer bought a number of equally priced cows at $480. After 3 died, the farmer sold the remaining cows for a total of $495 and the price per cow was $1 more when he sold them than when he bought them. We need to find the number of cows he bought originally.

Let, 'x' be the number of cows he bought originally each at a price of '$y'.

Then, we have

$xy=480,\\\\(x-3)(y+1)=495.$

Subtracting the first equation from the second, we have

$(x-3)(y+1)-xy=495-480\\\\\Rightarrow xy-3y+x-3-xy=15\\\\\Rightarrow x-3y-3=15\\\\\Rightarrow \dfrac{480}{y}-3y-3=15\\\\\Rightarrow y^2+6y-160=0\\\\\Rightarrow (y-10)(y+16)=0.$

This gives, y = 10  or  y = -16. Since price of a cow cannot be negative, so y = 10.

Thus, $x=\dfrac{480}{10}=48.$

Thus, the total number of cows originally bought is 48.