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Margaret [11]
3 years ago
7

Maya is taking her friends to a concert each ticket costs $25 and souvenir t-shirts are $12 each there is a $4 service fee for t

he entire purchase she has $130 if she buys 3 tickets what is the maximum number of t-shirts she can buy
Mathematics
2 answers:
defon3 years ago
6 0

Answer:

4.

Step-by-step explanation:

Let x be the number of t-shirts that Maya can buy.

We have been given that Maya is taking her friends to a concert each ticket costs $25 and souvenir t-shirts are $12 each.

Since 1 t-shirt costs $12, so cost of x t-shirts wold be 12x.

We have been given that Maya bought 3 tickets, so amount spent on 3 tickets would be \$25\times 3=\$75.

We are also told that there is a $4 service fee for the entire purchase, so we can represent our given information in an inequality as:

12x+75+3\leq 130

12x+78\leq 130

12x+78-78\leq 130-78

12x\leq 52

\frac{12x}{12}\leq \frac{52}{12}

x\leq 4.33333

Therefore, the maximum number of t-shirts that Maya can buy is 4.

LuckyWell [14K]3 years ago
5 0

Answer:


Step-by-step explanation: 3 T-shirts=75+4 (4 is the service fee) 130-79= 51. 51/12= 4 (I think it’s right)


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Implicit differentiation of 1/x +1/y=5 y(4)= 4/19<br> y'(4)=?
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Above, I changed the fraction form of x and y into exponential form so it is easier to see the differentiation. Now, we can differentiate:

-1x^{-2}+-1y^{-2}\frac{dy}{dx}=5\\\\\frac{-1}{x^2}-\frac{1}{y^2}\frac{dy}{dx}=5\\\\-\frac{1}{y^2}\frac{dy}{dx}=5+\frac{1}{x^2}\\\\\frac{dy}{dx}=-5y^2-\frac{y^2}{x^2}

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5 0
3 years ago
1 Point
I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

\text { Volume of a cylinder }=\pi r^{2} h

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e  

\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}

<em><u>Ratio for the volumes of two cylinders</u></em>

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}

Cancelling the common terms, we get

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)

Substituting we get,

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}

Hence, the ratio of volume of two cylinders is 8 : 27

7 0
3 years ago
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